Android程序查询包含“*" "#”的号码时出错的解决措施
发布时间:2021-11-23 13:44:19 所属栏目:PHP教程 来源:互联网
导读:代码错误提示: E/AndroidRuntime(1145): Caused by: android.database.sqlite.SQLiteException: near *: syntax error: , while compiling: SELECT numbertype, new, duration, _id, numberlabel, name, number, type, date FROM calls WHERE (number = **9)
代码错误提示: E/AndroidRuntime(1145): Caused by: android.database.sqlite.SQLiteException: near "*": syntax error: , while compiling: SELECT numbertype, new, duration, _id, numberlabel, name, number, type, date FROM calls WHERE (number = **9) ORDER BY date desc 解决: strQuery = "number = " + strQueryNumber; callLogCursor = TApplication.nowTApplication.getContentResolver() .query(CallLog.Calls.CONTENT_URI, null, strQuery, null, "date desc"); 查询代码改成: strQuery = "number = " + "'strQueryNumber'"; callLogCursor = TApplication.nowTApplication.getContentResolver() .query(CallLog.Calls.CONTENT_URI, null, strQuery, null, "date desc"); 总结:因为"*"为数据库里的关键字(未经证实),所有查找是会报语法错误,只需要拼接字符串,把"*"改成非关键字即可 ps:模拟器不知道为何直接拔打数字+"#"会清空屏幕,而只能拨打"#"开头的号码 ![]() (编辑:云计算网_泰州站长网) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |